- 3 ∶ 5
- 2 ∶ 5
- 3 ∶ 2
- 2 ∶ 3

Option 2 : 2 ∶ 5

**Given∶**

_{3}

**Formula Used∶**

F = Fraction of HCL in final mixture,

I = Fraction of HCL in initial mixture

X = Quantity of mixture replaced.

V = Total volume of mixture.

**Calculation∶**

F = I (1 - X/V), where

F = 1/2, I = 5/6, X/V = ?

Put all the values in the above given formula, we get

⇒ 1/2 = 5/6 × [1 - X/V]

⇒ 1/2 × 6/5 = 1 - X/V

⇒ X/V = 1 - 3/5

⇒ X/V = 2/5

**∴ The required ratio is 2 ∶ 5.**

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